1956 tennis event results
First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the women's singles tennis title at the 1956 U.S. National Championships.[2][3]
Seeds
The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.
- Shirley Fry (champion)
- Althea Gibson (finalist)
- Louise Brough (quarterfinals)
- Dorothy Knode (quarterfinals)
- Margaret duPont (quarterfinals)
- Shirley Bloomer (semifinals)
- Betty Pratt (semifinals)
- Darlene Hard (quarterfinals)
Draw
Key
Final eight
References